Exercise 3 Solution

Exercise 3 Solution
isit = (0 ≤ x && x ≤ 10)
Solution Explanation:
  • Uses the logical AND operator && to combine two conditions
  • 0 ≤ x checks if x is greater than or equal to 0
  • x ≤ 10 checks if x is less than or equal to 10
  • The entire expression evaluates to logical true if both conditions are true
  • Automatically evaluates to logical false if either condition is false
Alternative Approach:
% Using & operator (element-wise AND)
isit = (0 ≤ x) & (x ≤ 10);

Note: && is preferred for scalar comparisons as it uses short-circuit evaluation.

Both solutions demonstrate good programming practices with proper validation and clear logic!


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