Exercise with solutions on Mole and Molar Mas

Question:

Arrange the following samples in order of increasing numbers of C atoms:

12 g ¹²C
Solution: the number of atoms in exactly 12 grams of isotopically pure ¹²C,
is equal to 6.02 × 10²³ carbon atoms.
1 mol C₄H₄
Solution: 1 mol C₄H₄ = 6.02 × 10²³ molecules of C₄H₄
which means there 4 × 6.02 × 10²³ molecules of C = 24 × 10²³ molecules of C
9 × 10²³molecules of CO₂
Solution: Same number which is 9 × 10²³molecules of CO₂

So, the arrangement in order of increasing numbers of C atoms is as follows:
12 g ¹²C (6.02 × 10²³) < 9 × 10²³molecules of CO₂) < 1 mol C₄H₄ (24 × 10²³ molecules of C)

Exercise on Mole & Molar Mas: Solutions

Question: